Python 删除list列表中出现的任何空列表的方法

示例列表；

i = [[1,2,3,[]],[],[],[],[4,5,[],7]]

输出结果：

[[1,2,3],[4,5,7]]

1、使用递归实现

使用递归，可以删除任何深度的空列表:

def remove_nested_list(listt):
    for index, value in enumerate(reversed(listt)):
        if isinstance(value, list) and value != []:
            remove_nested_list(value)
        elif isinstance(value, list) and len(value) == 0:
            listt.remove(value)

a = [[1, 2, 3, 0, []], [], [], [], [4, 5, [], 7]]
print(f"before-->{a}")
remove_nested_list(a)
print(f"after-->{a}")

输出：

before-->[[1, 2, 3, 0, []], [], [], [], [4, 5, [], 7]]
after-->[[1, 2, 3, 0], [4, 5, 7]]

或者

a = [[1,2,3,[]],[],[],[],[4,5,[],7]]

def nested_check(alist):
    for item in alist[:]:
        if item == []:
            alist.remove(item)
        elif isinstance(item, list):
            nested_check(item)

nested_check(a)
print(a)

或者

def empty(lst):
    if lst == []:
        return True
    elif isinstance(lst, list):
        return all(empty(i) for i in lst)
    else:
        return False
def remove_empty(lst):
    return (
        [remove_empty(i) for i in lst if not empty(i)]
        if isinstance(lst, list)
        else lst
    )
i = [[1,2,3,[]],[],[],[],[4,5,[],7]]
remove_empty(i)
remove_nested_list(i) 
print(i) # [[1, 2, 3, []]]
ii = [[1,2,3,[]],[],[],[],[4,5,[],7]]
remove_empty(ii)
remove_nested_list(ii) 
print(ii) 

2、确定深度的方法

i = [[1,2,3,[]],[],[],[],[4,5,[],7]]
print([[j for j in ele if j] for ele in i if ele])

或者

a = [[1,2,3,[]],[],[],[],[4,5,[],7]]
print('list before:', a)
while [] in a:
    for i in a:
        if i == []:
            a.remove(i)
for i in a:
    for e in i:
        if e == []:
            i.remove(e)
print('list after:', a)